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6a3a1fe147
Apparently in C, if you have `void test();`, it's completely okay to do `test(2);`. The function will take in the argument, but just discard it and throw it away. It's like a trash can, and a rude one at that. If you declare it like `void test(void);`, this is prevented. This is not a problem in C++ - doing `void test();` and `test(2);` is guaranteed to result in a compile error (this also means that right now, at least in all `.cpp` files, nobody is ever calling a void parameter function with arguments and having their arguments be thrown away). However, we may not be using C++ in the future, so I just want to lay down the precedent that if a function takes in no arguments, you must explicitly declare it as such. I would've added `-Wstrict-prototypes`, but it produces an annoying warning message saying it doesn't work in C++ mode if you're compiling in C++ mode. So it can be added later.
36 lines
416 B
C
36 lines
416 B
C
#include "MakeAndPlay.h"
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#ifndef MAKEANDPLAY
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#include <stdint.h>
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/* Totally unimplemented right now! */
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int32_t GOG_init(void)
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{
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return 0;
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}
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void GOG_shutdown(void)
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{
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}
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void GOG_update(void)
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{
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}
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void GOG_unlockAchievement(const char *name)
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{
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}
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int32_t GOG_getAchievementProgress(const char *name)
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{
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return 0;
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}
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void GOG_setAchievementProgress(const char *name, int32_t stat)
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{
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}
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#endif /* MAKEANDPLAY */
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