Add solver
It's fragile in ways, let's make it better with more specs
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5 changed files with 76 additions and 11 deletions
8
Main.hs
8
Main.hs
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@ -6,6 +6,7 @@ import Data.Attoparsec.Text (parseOnly)
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import qualified Data.Text.IO as T
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import INAST
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import INSolver
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main :: IO ()
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main = do
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@ -13,4 +14,9 @@ main = do
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T.putStrLn "Using the following input network:"
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T.putStrLn inputNetwork
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T.putStrLn "Parsed AST:"
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print (parseOnly insuranceNetworkParser inputNetwork)
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let Right insnet = parseOnly insuranceNetworkParser inputNetwork
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print insnet
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T.putStrLn "Problem solution, input=3:"
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print $ solve (3::Int) insnet
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T.putStrLn "Problem solution, input=6:"
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print $ solve (6::Int) insnet
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15
desc.md
15
desc.md
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@ -20,7 +20,10 @@ The following grammar:
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is used to represents insurance networks.
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Given a single input of type `Int`, the job of these networks is to provide, if possible, exactly 100% underwriting capital using the fewest insurers possible. Each insurer contributes their percentage only if their respective conditions are met.
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Given a single input of type `Int`, the job of these networks is to provide, if
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possible, exactly 100% underwriting capital using the fewest insurers possible.
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Each insurer contributes their percentage only if their respective conditions
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are met.
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Below is a simple example of such a network:
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@ -39,7 +42,8 @@ where:
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- `I3` contributes 40% only if `I1` contributes
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- etc...
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Given the above, your task is to write a small command line program that takes 2 parameters:
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Given the above, your task is to write a small command line program that takes 2
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parameters:
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- the path to a file that defines a network
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- an integer input to the network
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@ -49,8 +53,11 @@ Eg. if your program was given the above example network and:
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- input `3` then it would output `[1, 2]` (representing insurers `I1` and `I2`)
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- input `6` then it would output `[1, 3, 6]`
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If a network is unable to collect exactly 100% for a given input then your program should output `[]`.
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If a network is unable to collect exactly 100% for a given input then your
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program should output `[]`.
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Please create a new private github repository named `artificial-network`, commit all your code there and once finished please invite me, `pwm`, so we can check your solution.
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Please create a new private github repository named `artificial-network`, commit
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all your code there and once finished please invite me, `pwm`, so we can check
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your solution.
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Good luck!
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@ -6,6 +6,7 @@ dependencies:
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- base == 4.*
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- attoparsec
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- text
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- mtl
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executables:
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in23:
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@ -17,4 +18,5 @@ library:
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source-dirs: src
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exposed-modules:
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- INAST
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- INSolver
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22
src/INAST.hs
22
src/INAST.hs
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@ -1,4 +1,5 @@
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{-# LANGUAGE OverloadedStrings #-}
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{-# LANGUAGE DeriveFoldable #-}
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{-# OPTIONS_GHC -Wno-unused-do-bind #-}
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module INAST where
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@ -49,7 +50,11 @@ insuranceNetworkParser = many1 line
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type InsuranceNetworkAST = [INASTLine]
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data INASTLine = INASTLine INASTInsurerId INASTPercent [INASTExpr]
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data INASTLine =
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INASTLine { unINASTLineInsurerId :: INASTInsurerId
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, unINASTLinePercent :: INASTPercent
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, unINASTLineExprs :: [INASTExpr]
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}
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deriving (Show)
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data INASTExpr = INASTExprLt INASTLt
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@ -64,7 +69,14 @@ newtype INASTGt = INASTGt Int
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deriving (Show)
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newtype INASTEq = INASTEq Int
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deriving (Show)
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newtype INASTInsurerId = INASTInsurerId Int
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deriving (Show)
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newtype INASTPercent = INASTPercent Int
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deriving (Show)
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newtype INASTInsurerId = INASTInsurerId { unNASTInsurerId :: Int }
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deriving (Eq)
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instance Show INASTInsurerId where
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show (INASTInsurerId i) = "I" ++ show i
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newtype INASTPercent = INASTPercent { unINASTPercent :: Int }
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instance Show INASTPercent where
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show (INASTPercent p) = show p ++ "%"
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38
src/INSolver.hs
Normal file
38
src/INSolver.hs
Normal file
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@ -0,0 +1,38 @@
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{-# OPTIONS_GHC -Wno-missing-signatures #-}
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module INSolver where
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import Control.Monad
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import Control.Monad.State
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import Data.List (tails,find)
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import INAST
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-- solve :: Int -> InsuranceNetworkAST -> [INASTInsurerId]
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solve i = maybe [] (map unNASTInsurerId . reverse . fst)
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. find ((== 100) . snd)
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. map foldMe
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. tails
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. flip execState []
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. mapM potentialInsId
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where
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foldMe :: [(INASTInsurerId,INASTPercent)] -> ([INASTInsurerId],Int)
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foldMe = foldr (\ (i',INASTPercent p) (ixacc,pacc) -> (i':ixacc,p+pacc)) ([],0)
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-- | Result is sensitive to order of execution.
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-- One thing not speficied in the problem statement is whether expressions
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-- only apply to previous lines, or if they can be looking forward
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-- Here we're assuming the former case holds true.
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potentialInsId :: INASTLine -> State [(INASTInsurerId,INASTPercent)] ()
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potentialInsId (INASTLine iid pct exprs) = do
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insidpctx <- get
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when (allExprEval i insidpctx exprs) (modify ((iid,pct) :))
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allExprEval :: Int -> [(INASTInsurerId,INASTPercent)] -> [INASTExpr] -> Bool
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allExprEval i xs = all (exprEval i (map fst xs))
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exprEval :: Int -> [INASTInsurerId] -> INASTExpr -> Bool
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exprEval i _ (INASTExprLt (INASTLt n)) = i < n
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exprEval i _ (INASTExprGt (INASTGt n)) = i > n
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exprEval i _ (INASTExprEq (INASTEq n)) = i == n
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exprEval _ insx (INASTExprInsurerId insid) = insid `elem` insx
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