Add solver

It's fragile in ways, let's make it better with more specs
This commit is contained in:
Samae 2023-12-04 23:49:58 +02:00
parent 3ad26674d3
commit ebdb931e32
5 changed files with 76 additions and 11 deletions

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@ -6,6 +6,7 @@ import Data.Attoparsec.Text (parseOnly)
import qualified Data.Text.IO as T
import INAST
import INSolver
main :: IO ()
main = do
@ -13,4 +14,9 @@ main = do
T.putStrLn "Using the following input network:"
T.putStrLn inputNetwork
T.putStrLn "Parsed AST:"
print (parseOnly insuranceNetworkParser inputNetwork)
let Right insnet = parseOnly insuranceNetworkParser inputNetwork
print insnet
T.putStrLn "Problem solution, input=3:"
print $ solve (3::Int) insnet
T.putStrLn "Problem solution, input=6:"
print $ solve (6::Int) insnet

17
desc.md
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@ -20,7 +20,10 @@ The following grammar:
is used to represents insurance networks.
Given a single input of type `Int`, the job of these networks is to provide, if possible, exactly 100% underwriting capital using the fewest insurers possible. Each insurer contributes their percentage only if their respective conditions are met.
Given a single input of type `Int`, the job of these networks is to provide, if
possible, exactly 100% underwriting capital using the fewest insurers possible.
Each insurer contributes their percentage only if their respective conditions
are met.
Below is a simple example of such a network:
@ -39,7 +42,8 @@ where:
- `I3` contributes 40% only if `I1` contributes
- etc...
Given the above, your task is to write a small command line program that takes 2 parameters:
Given the above, your task is to write a small command line program that takes 2
parameters:
- the path to a file that defines a network
- an integer input to the network
@ -49,8 +53,11 @@ Eg. if your program was given the above example network and:
- input `3` then it would output `[1, 2]` (representing insurers `I1` and `I2`)
- input `6` then it would output `[1, 3, 6]`
If a network is unable to collect exactly 100% for a given input then your program should output `[]`.
If a network is unable to collect exactly 100% for a given input then your
program should output `[]`.
Please create a new private github repository named `artificial-network`, commit all your code there and once finished please invite me, `pwm`, so we can check your solution.
Please create a new private github repository named `artificial-network`, commit
all your code there and once finished please invite me, `pwm`, so we can check
your solution.
Good luck!
Good luck!

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@ -6,6 +6,7 @@ dependencies:
- base == 4.*
- attoparsec
- text
- mtl
executables:
in23:
@ -17,4 +18,5 @@ library:
source-dirs: src
exposed-modules:
- INAST
- INSolver

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@ -1,4 +1,5 @@
{-# LANGUAGE OverloadedStrings #-}
{-# LANGUAGE DeriveFoldable #-}
{-# OPTIONS_GHC -Wno-unused-do-bind #-}
module INAST where
@ -49,7 +50,11 @@ insuranceNetworkParser = many1 line
type InsuranceNetworkAST = [INASTLine]
data INASTLine = INASTLine INASTInsurerId INASTPercent [INASTExpr]
data INASTLine =
INASTLine { unINASTLineInsurerId :: INASTInsurerId
, unINASTLinePercent :: INASTPercent
, unINASTLineExprs :: [INASTExpr]
}
deriving (Show)
data INASTExpr = INASTExprLt INASTLt
@ -64,7 +69,14 @@ newtype INASTGt = INASTGt Int
deriving (Show)
newtype INASTEq = INASTEq Int
deriving (Show)
newtype INASTInsurerId = INASTInsurerId Int
deriving (Show)
newtype INASTPercent = INASTPercent Int
deriving (Show)
newtype INASTInsurerId = INASTInsurerId { unNASTInsurerId :: Int }
deriving (Eq)
instance Show INASTInsurerId where
show (INASTInsurerId i) = "I" ++ show i
newtype INASTPercent = INASTPercent { unINASTPercent :: Int }
instance Show INASTPercent where
show (INASTPercent p) = show p ++ "%"

38
src/INSolver.hs Normal file
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@ -0,0 +1,38 @@
{-# OPTIONS_GHC -Wno-missing-signatures #-}
module INSolver where
import Control.Monad
import Control.Monad.State
import Data.List (tails,find)
import INAST
-- solve :: Int -> InsuranceNetworkAST -> [INASTInsurerId]
solve i = maybe [] (map unNASTInsurerId . reverse . fst)
. find ((== 100) . snd)
. map foldMe
. tails
. flip execState []
. mapM potentialInsId
where
foldMe :: [(INASTInsurerId,INASTPercent)] -> ([INASTInsurerId],Int)
foldMe = foldr (\ (i',INASTPercent p) (ixacc,pacc) -> (i':ixacc,p+pacc)) ([],0)
-- | Result is sensitive to order of execution.
-- One thing not speficied in the problem statement is whether expressions
-- only apply to previous lines, or if they can be looking forward
-- Here we're assuming the former case holds true.
potentialInsId :: INASTLine -> State [(INASTInsurerId,INASTPercent)] ()
potentialInsId (INASTLine iid pct exprs) = do
insidpctx <- get
when (allExprEval i insidpctx exprs) (modify ((iid,pct) :))
allExprEval :: Int -> [(INASTInsurerId,INASTPercent)] -> [INASTExpr] -> Bool
allExprEval i xs = all (exprEval i (map fst xs))
exprEval :: Int -> [INASTInsurerId] -> INASTExpr -> Bool
exprEval i _ (INASTExprLt (INASTLt n)) = i < n
exprEval i _ (INASTExprGt (INASTGt n)) = i > n
exprEval i _ (INASTExprEq (INASTEq n)) = i == n
exprEval _ insx (INASTExprInsurerId insid) = insid `elem` insx